This is year 2200AD. Science has progressed a lot in two hundred years. Two hundred years is mentioned here because this problem is being sent back to 2000AD with the help of time machine. Now it is possible to establish direct connection between man and computer CPU. People can watch other peoples dream on 3D displayer (That is the monitor today) as if they were watching a movie. One problem in this century is that people have become so dependent on computers that their analytical ability is approaching zero. Computers can now read problems and solve them automatically. But they can solve only difficult problems. There are no easy problems now. Our chief scientist is in great trouble as he has forgotten the number of his combination lock. For security reasons computers today cannot solve combination lock related problems. In a mid-summer night the scientist has a dream where he sees a lot of unsigned integer numbers flying around. He records them with the help of his computer, Then he has a clue that if the numbers are (X1, X2, . . . , Xn) he will have to find an integer number
A (This A is the combination lock code) such that
(|X1 − A| + |X2 − A| + . . . + |Xn − A|)
is minimum.
Input will contain several blocks. Each block will start with a number n (0 < n ≤ 1000000) indicating how many numbers he saw in the dream. Next there will be n numbers. All the numbers will be less that 65536. The input will be terminated by end of file.
For each set of input there will be one line of output. That line will contain the minimum possible value for A. Next it will contain how many numbers are there in the input that satisfy the property of A (The summation of absolute deviation from A is minimum). And finally you have to print how many possible different integer values are there for A (these values need not be present in the input). These numbers will be separated by single space.
1.這題要輸出三個數，分別為最小的中位數、數列中滿足條件的數量、滿足條件的數字(不一定要在數列中)
2.切記要記得先排序，mid1,mid2都為中位數，不同的是若數列數量為偶數，中位數有兩個 (注意mid2的算法為(n-1)/2)
3.第一個數一定是mid2，因為mid2是小的中位數、第二個數只要數列中有與中位數相同的數就+1、第三個數為兩個中位數之間所有的整數
Sample Output 1
2
10
10
4
1
2
2
4
10 2 1
2 2 1